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NCERT Class XII Chapter
Dual Nature of Radiation and Matter
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Question : 3 of 37
Marks: +1, -0
The photoelectric cut-off voltage in a certain experiment is 1.5 V. What is the maximum kinetic energy of photoelectrons emitted?
Solution:  
Here V0V_0 = 1.5 V
KmaxK_{max} = eV0eV_0 = 1.5 eV = 1.5 × 1.6 × 10−1910^{-19} J = 2.4 × 10−1910^{-19} J
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