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Question : 27
Total: 27
A bat is flitting about in a cave, navigating via ultrasonic beeps. Assume that the sound emission frequency of the bat is 40 kHz. During one fast swoop directly towards a flat wall surface, the bat is moving at 0.03 times the speed of the sound in air. What frequency does the bat hear reflected off the wall?
Solution:  
Here, υ=40‌kHz,
speed of sound in air, v=340ms–1
∴ v′= speed of bat
=0.03×v =0.03×340=10.20ms–1
The bat moving towards wall acts as a moving source and for the sound waves reflected from the wall, it acts as a moving observer. Thus the source and observer are approaching each other with same speed.
i.e. vs=v0=v′=10.2ms−1
Thus apparent frequency of the reflected sound waves heard by the bat is given by
υ′=
v+v0
v−vs
×υ
=
340+10.2
340−10.2
×40‌kHz

=
350.2
329.8
×40
=42.47‌kHz
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