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Question : 20
Total: 27
A train, standing at the outer signal of a railway station blows a whistle of frequency 400 Hz in still air.
(i) What is the frequency of the whistle for a platform observer when the train
(a) approaches the platform with a speed of 10ms1.
(b)recedes from the platform with a speed of 10ms1?
(ii) What is the speed of sound in each case? The speed of sound in still air can be taken as 340 ms1.
Solution:  
Here, frequency of source of sound,
υ=400 Hz; v=340ms1 = speed of sound
Speed of source =vs=10ms1
(i) (a) When the train approaches the platform, the apparent frequency as heard by the observer on the platformwill be
υ=
v
vvs
υ
=
340
34010
×400

=
340
330
×400
=412.1Hz

(b) When the train recedes from the platform, the apparent frequency as heard by the observer is given by according to the formula :
υ=
v
v+vs
υ
=
340
340+10
×400

=
340
350
×400
=388.6 Hz
=389Hz

(ii) The speed of sound in each case remains same i.e. 340ms1.
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