© examsnet.com
Question : 26 of 27
Marks: +1, -0
Earthquakes generate sound waves inside the earth. Unlike a gas, the earth can experience both transverse (S) and longitudinal (P) sound waves. Typically the speed of S wave is about 4.0 km s−14.0\ \mathrm{km}\,\mathrm{s}^{-1}, and that of P wave is 8.0 km s−18.0\ \mathrm{km}\,\mathrm{s}^{-1}. A seismograph records P and S waves from an earthquake. The first P wave arrives 4 min before the first S wave. Assuming the waves travel in straight line, at what distance does the earthquake occur?
Solution:  
Let v1,v2v_1, v_2 be the velocities of S waves and P waves, and t1,t2t_1, t_2 be the time taken by these waves to travel to the position of seismograph. If ll is the distance of occurrence of earthquake from the seismograph, then
l=v1t1=v2t2l=v_1 t_1=v_2 t_2...(i)
Now, v1=4 km s−1v_1=4\ \mathrm{km}\,\mathrm{s}^{-1} and v2=8 km s−1v_2=8\ \mathrm{km}\,\mathrm{s}^{-1}...(ii)
∴4t1=8t2\therefore 4 t_1=8 t_2 or t1=2t2t_1=2 t_2
Also, t1−t2=4 min=240 st_1-t_2=4\ \mathrm{min}=240\ \mathrm{s}
Using (ii), 2t2−t2=240 s; t2=240 s2 t_2-t_2=240\ \mathrm{s};\ t_2=240\ \mathrm{s}
t1=2×t2=2×240=480 st_1=2\times t_2=2\times 240=480\ \mathrm{s}
Now, from (i) l=v1t1=4×480=1920 kml=v_1 t_1=4\times 480=1920\ \mathrm{km}
Hence earthquake occurs 1920 km away from the seismograph.
© examsnet.com
Go to Question: