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Question : 24 of 33
Marks: +1, -0
When the planet Jupiter is at a distance of 824.7 million kilometers from the Earth, its angular diameter is measured to be 35.72” of arc. Calculate the diameter of Jupiter.
Solution:  
Here, r=824.7×106 kmr=824.7 \times 10^{6} \text{ km}
θ=35.72∘\theta = 35.72^{\circ}
=35.7260×60×π180= \frac{35.72}{60 \times 60} \times \frac{\pi}{180} radian,
Diameter, D=?D=?
As D=rθD = r \theta
∴D=824.7×106×35.72×π60×60×180 km\therefore D = 824.7 \times 10^{6} \times \frac{35.72 \times \pi}{60 \times 60 \times 180} \text{ km}
=1.429×105 km=1.429 \times 10^{5} \text{ km}
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