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Oscillations

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Question : 11 of 25
Marks: +1, -0
Figures (a) and (b) correspond to two circular motions. The radius of the circle, the period of revolution, the initial position, and the sense of revolution (i.e. clockwise or anti-clockwise) are indicated on each figure.
Obtain the corresponding simple harmonic motions of the x-projection of the radius vector of the revolving particle P, in each case.
Solution:  
In figure (a) T = 2 s; A = 3 cm
At t = 0, OP makes angle π2\frac{\pi}{2} with x-axis, i.e. =π2=\frac{\pi}{2} radian. While moving clockwise, here ϕ=+π2\phi = +\frac{\pi}{2}. Thus the x-projection of OP at time t will give us the equation of simple harmonic motion, given by
x=Acos(2πtT+π)x = A \cos\left( \frac{2\pi t}{T} + \pi \right) =3cos(2ϕt2+π2)= 3 \cos\left( \frac{2\phi t}{2} + \frac{\pi}{2} \right)
or x=3sin(πt)x = -3 \sin(\pi t) (where x is in cm)
In figure (b) T = 4 s ; A = 2 m
At t = 0, OP makes an angle p with the positive direction of x-axis, i.e. ϕ=π\phi = \pi. While moving anticlockwise, here ϕ=+π\phi = +\pi.
Thus the x-projection of OP at time t will give us the equation of simple harmonic motion given by
x=Acos(2πtT+ϕ)x = A \cos\left( \frac{2\pi t}{T} + \phi \right) =2cos(2πt4+π)=2cos(π2t)= 2 \cos\left( \frac{2\pi t}{4} + \pi \right) = -2 \cos\left( \frac{\pi}{2} t \right)
(where x is in m)
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