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Laws of Motion

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Question : 18 of 40
Marks: +1, -0
Two billiard balls each of mass 0.05 kg moving in opposite directions with speed 6 m s−1^{-1} collide and rebound with the same speed. What is the impulse imparted to each ball due to the other?
Solution:  
Let the two balls A and B moving in opposite directions collide and rebound with same speed.
Initial momentum of the ball A = 0.05 × (6) = 0.3 kg m s −1^{-1}
Final momentum of the ball A = 0.05(–6) = –0.3 kg m s−1^{-1}
Impulse imparted to ball A = change in momentum of ball
A=A= final momentum - initial momentum =−0.3−0.3=−0.6kgms−1=-0.3-0.3=-0.6 \text{kg} \text{m} \text{s}^{-1}
Initial momentum of the ball B=0.05×(−6)=−0.3kgms−1B=0.05 \times(-6)=-0.3 \text{kg} \text{m} \text{s}^{-1}
Final momentum of the ball B=0.05×(6)=0.3kgms−1B=0.05\times(6)=0.3 \text{kg} \text{m} \text{s}^{-1}
Impulse imparted due to B=0.3−(−0.3)=0.6kgms−1B=0.3-(-0.3)=0.6 \text{kg} \text{m} \text{s}^{-1}
Impulse on each ball is 0.6 kgms−1\text{kg} \text{m} \text{s}^{-1} in magnitude but these two impulses are opposite in direction.
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