Gravitation

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Question : 19
Total: 25
A satellite orbits the earth at a height of 400 km above the surface. How much energy must be expended to rocket the satellite out of the earth’s gravitational influence?
Mass of the satellite = 200 kg; mass of the earth =6.0×1024kg;
radius of the earth =6.4×106m; G=6.67×1011Nm2kg2.
Solution:  
Total energy of orbiting satellite at a height h
=
GMm
(R+h)
+
1
2
m
v2

=
GMm
(R+h)
+
1
2
m
GM
(R+h)

=
GMm
2(R+h)

Energy expended to rocket the satellite out of the earth’s gravitational field =– (total energy of the orbiting satellite)
=
GMm
2(R+h)

=
(6.67×1011)×(6×1024)×200
2(6.4×106+4×105)

=5.9×109J
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