A value of x satisfying tanx = $\sqrt{3}$ is $\frac{\pi}{3}$ Principal Solution : We know that tan $\frac{\pi}{3}$ = $\sqrt{3}$ and tan $\left(\pi+\frac{\pi}{3}\right)$ = tan $\frac{\pi}{3}$ = $\sqrt{3}$ Thus, tan $\frac{\pi}{3}$ = tan $\frac{4\pi}{3}$ = $\sqrt{3}$ Therefore principal solutions are $\frac{\pi}{3},\frac{4\pi}{3}$ General Solution : We know that tan $\frac{\pi}{3}$ = $\sqrt{3}$ Therefore tanx = $\sqrt{3}$ ⇒ tan x = $\frac{\pi}{3}$ ⇒ x = nπ + $\frac{\pi}{3}$ , n ∊ Z [Since If tanθ = tanα, then θ = n π + α, n ∈ Z]