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NCERT Class XI Mathematics - Trigonometric Functions - Solutions

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Question : 29 of 61
Marks: +1, -0
sin2sin^2 6x – sin2sin^2 4x = sin2x sin10x
Solution:  
We have , L.H.S. = sin2sin^2 6x – sin2sin^2 4x
= sin (6x - 4x) sin (6x + 4x) [Since sin2sin^2 A - sin2sin^2 B = sin (A + B) sin (A - B)]
= sin 2x sin 10x = R.H.S.
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