Suppose the given points are A and B. Let M be the mid point of AB. ∴ M = $\left( \frac{3+(-1)}{2}, \frac{4+2}{2} \right)$ = (1 , 3) Slope of AB = $\frac{2-4}{-1-3}$ = $\frac{-2}{-4}$ = $\frac{1}{2}$ ∴ Slope of the right bisector is –2. Since the right bisector passes through M(1, 3), ∴ The equation of the right bisector is y – 3 = –2 (x – 1) ⇒ 2x + y – 5 = 0 Hence the required equation is 2x + y = 5.