Let AB be the given line segment making intercepts a and b on the x-axis & y-axis respectively. Then, the equation of line AB is $\frac{x}{a}+\frac{y}{b}$ = 1 So, these points are A(a, 0) and B(0, b). Now, R(h, k) divides the line segment AB in the ratio 1 : 2. $\frac{1\times 0+2\times a}{1+2}$ = h and $\frac{1\times b+2\times 0}{1+2}$ = k ⇒ a = $\frac{3h}{2}$ and b = 3k So, the required equation of the line is $\frac{x}{\frac{3h}{2}}+\frac{y}{3k}$ = 1 ⇒ $\frac{2x}{3h}+\frac{y}{3k}$ = 1