We know that the equation of a line with slope m and passing through the point $(x_0, y_0)$ is given by (y – $y_0$) = m(x – $x_0$) Here,m = tan 75° = 2+ $\sqrt{3}$, $x_0$ = 2, $y_0$ = 2 $\sqrt{3}$ Hence, required equation is (y - $2\sqrt{3}$) = (2 + $\sqrt{3}$) (x - 2) ⇒ y - $2\sqrt{3}$ = 2x + $\sqrt{3}x$ - 4 - $2\sqrt{3}$ ⇒ $(2+\sqrt{3})x$ - y - 4 = 0