We know that the equation of a line with slope m and passing through the point $(x_0, y_0)$ is given by $(y - y_0)$ = m $(x - x_0)$. Here m = $\frac{1}{2}$ , $x_0$ = - 4 , $y_0$ = 3 Hence, the required equation is (y - 3) = $\frac{1}{2}$ (x + 4) ⇒ 2y - 6 = x + 4 ⇒ x - 2y + 10 = 0