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NCERT Class XI Mathematics - Statistics - Solutions

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Question : 26 of 34
Marks: +1, -0
The following is the record of goals scored by team A in a football session:
No. of goals scored01 2 3 4
No. of matches 1 9 7 5 3
For the team B, mean number of goals scored per match was 2 with a standard deviation 1.25 goals. Find which team may be considered more consistent?
Solution:  
For team A :
xix_i fif_i fixif_i x_i fixi2f_i x_i^2
0 1 00
19 9 9
2 7 14 28
3 5 1545
4 312 48
2550 130
Mean (xA‾)(\overline{x_A}) = 1N∑fixi\frac{1}{N} \sum f_i x_i = 125\frac{1}{25} × 50 = 2 ; S.D. (σA)(\sigma_A) = ∑fixi2N−(∑fixiN)2\sqrt{ \frac{ \sum f_i x_i^2 }{ N } - \left( \frac{ \sum f_i x_i }{ N } \right)^2 }
= 13025−(5025)2\sqrt{ \frac{130}{25} - \left( \frac{50}{25} \right)^2 }
= 5.2−4\sqrt{5.2 - 4} = 1.2\sqrt{1.2} = 1.09
∴ C.V. of team A = 1.092\frac{1.09}{2} × 100 = 54.5
C.V. of team B= 1.252\frac{1.25}{2} × 100 = 62.5
Since C.V. of team A < C.V. of team B. Thus team A is more consistent.
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