NCERT Class XI Mathematics - Sequences and Series - Solutions
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Question : 9
Total: 106
Solution:
We have, a n ( − 1 ) n − 1 n 3 ; a 9
Put n = 9,a 9 ( − 1 ) 9 − 1 ( 9 ) 3 ( − 1 ) 8 ( 729 )
Put n = 9,
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