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NCERT Class XI Mathematics - Sequences and Series - Solutions

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Question : 4
Total: 106
an =
2n−3
6
Solution:  
We have, an =
2n−3
6
Substituting n = 1, 2, 3, 4, 5, we get
a1 =
2.1−3
6
 =
2−3
6
 = -
1
6
 , a2 =
2.2−3
6
 =
4−3
6
 =
1
6
a3 =
2.3−3
6
 =
6−3
6
 =
3
6
 =
1
2
 , a4 =
2.4−3
6
 =
8−3
6
 =
5
6
a5 =
2.5−3
6
 =
10−3
6
 =
7
6
∴ The first five terms are -
1
6
,
1
6
,
1
2
,
5
6
,
7
6
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