We have, $a_1$ = 1 , $a_2$ = 1 , $a_3$ = $a_2+a_1$ = 1 + 1 = 2 $a_4$ = $a_3+a_2$ = 2 + 1 = 3 , $a_5$ = $a_4+a_3$ = 3 + 2 = 5 , $a_6$ = $a_5+a_4$ = 5 + 3 = 8 Now, substitute n = 1, 2, 3, 4, 5 in $\frac{a_{n+1}}{a_n}$ , we obtain $\frac{a_2}{a_1}$ = $\frac{1}{1}$ = 1 , $\frac{a_3}{a_2}$ = $\frac{2}{1}$ = 2, $\frac{a_4}{a_3}$ = $\frac{3}{2}$ , $\frac{a_5}{a_4}$ = $\frac{5}{3}$ , $\frac{a_6}{a_5}$ = $\frac{8}{5}$.