Man deposited = Rs 10,000. Rate of interest = 5% Amount at the end of 1st year = Rs. $\left[10000+\frac{10000\times5\times1}{100}\right]$ Since A = P + $\left(\frac{P\times R\times T}{100}\right)$ = Rs. [10000 + 500] = Rs. 10500 Amount at the end of 2nd year = Rs. $\left[10000+\frac{10000\times5\times2}{100}\right]$ = Rs. [10000 + 1000] = Rs. 11000. Similarly, amount at the end of 14th year = Rs. $\left[10000+\frac{10000\times5\times14}{100}\right]$ = Rs. [10000 + 7000] = Rs. 17,000. Hence, the amount at the end of 14th year = amount in the 15th year = Rs. 17000. Now, amount at the end of 20th year = Rs. $\left[10000+\frac{10000\times5\times20}{100}\right]$ = Rs. [10000 + 10000] = Rs. 20000.