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NCERT Class XI Mathematics - Sequences and Series - Solutions

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Question : 10 of 106
Marks: +1, -0
ana_n = n(n−2)n+3;a20\frac{n(n-2)}{n+3} ; a_{20}
Solution:  
We have, ana_n = n(n−2)n+3;a20\frac{n(n-2)}{n+3} ; a_{20}
Put n = 20, a20a_{20} = 20(20−2)20+3\frac{20(20-2)}{20+3} = 20×1823\frac{20\times 18}{23} = 36023\frac{360}{23}
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