An experiment consists of tossing a coin marked 1 and 6 on either faces and rolling a die. ∴ The sample space of the experiment is given by S = {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)} (i) Let E be the event that sum of number is 3. E = {(1, 2)} ⇒ n(E) = 1 n(S) = 12 ∴ P (E) = $\frac{n(E)}{n(S)}$ = $\frac{1}{12}$ (ii) Let F be the event that sum of number is 12. ∴ F = {(6, 6)} ⇒ n(F) = 1 and n(S) = 12 ⇒ P (F) = $\frac{n(F)}{n(S)}$ = $\frac{1}{12}$