NCERT Class XI Mathematics - Permutations and Combinations - Solutions

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Question : 37
Total: 41
In an examination, a question paper consists of 12 questions divided into two parts i.e., Part I and Part II, containing 5 and 7 questions, respectively. A student is required to attempt 8 questions in all, selecting at least 3 from each part. In how many ways can a student select the questions ?
Solution:  
Since at least 3 questions are required to attempt from each part.
Therefore a student can attempt
(a) 3 questions from part I & 5 questions from part II
(b) 4 questions from part I & 4 questions from part II
(c) 5 questions from part I & 3 questions from part II
In case (a), selection can be made in
5
‌
C3
×
7
‌
C5
ways.
In case (b), selection can be made in
5
‌
C4
×
7
‌
C4
ways.
In case (c), selection can be made in
5
‌
C5
×
7
‌
C3
ways.
∴ The required no. of ways =
5
‌
C3
×
7
‌
C5
+
5
‌
C4
×
7
‌
C4
+
5
‌
C5
×
7
‌
C3
=
5!
3!2!
×
7!
5!2!
+
5!
4!1!
×
7!
4!3!
+
5!
5!0!
×
7!
3!4!

=
5×4
2
×
7×6
2
+ 5 ×
7×6×5
3×2
+ 1 ×
7×6×5
3×2
= 210 + 175 + 35 = 420
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