Total no. of cards = 52 No. of ace cards = 4; No. of non-ace cards = 48 ∴ One ace card out of 4 can be selected in $\,{}^{4}C_1$ ways. Remaining 4 cards out of 48 cards can be selected in $\,{}^{48}C_4$ ways. ∴ Required no. of ways of selecting 5 cards = $\,{}^{4}C_1 \times \,{}^{48}C_4$ = $\frac{4!}{3! \times 1!} \times \frac{48!}{4! \times 44!}$ = $\frac{48 \times 47 \times 46 \times 45}{6}$ = 778320