NCERT Class XI Mathematics - Limits and Derivatives - Solutions

Question : 52

Total: 72

px2+qx+r

ax+b

Solution:

Let f (x) =

px2+qx+r

ax+b

⇒ f (x) = (px2+qx+r)(ax+b)−1 ... (i)
Differentiating (i) with respect to x, we get

(f (x)) = (2px + q) (ax+b)−1 + (px2+qx+r)[(−1)(ax+b)−2a]
=

2px+q

(ax+b)

a(px2+qx+r)

(ax+b)2

(2px+q)(ax+b)−apx2−aqx−ar

(ax+b)2

2px2a+2pxb+aqx+bq−apx2−aqx−ar

(ax+b)2

apx2+2pxb+bq−ar

(ax+b)2

Go to Question:

Prev Question

Next Question