Test Index

NCERT Class XI Mathematics - Limits and Derivatives - Solutions

© examsnet.com
Question : 48 of 72
Marks: +1, -0
ax+bcx+d\frac{ax+b}{cx+d}
Solution:  
Let f (x) = ax+bcx+d\frac{ax+b}{cx+d} ... (i)
Differentiating (i) with respect to x, we get
ddx\frac{d}{dx} (f (x)) =
(cx+d)(ax+b)′−(ax+b)(cx+d)′(cx+d)2\frac{(cx+d)(ax+b)'-(ax+b)(cx+d)'}{(cx+d)^2}
= (cx+d)(a)−(ax+b)(c)(cx+d)2\frac{(cx+d)(a)-(ax+b)(c)}{(cx+d)^2}
= acx+ad−acx−bc(cx+d)2\frac{acx+ad-acx-bc}{(cx+d)^2}
= ad−bc(cx+d)2\frac{ad-bc}{(cx+d)^2}.
© examsnet.com
Go to Question:
Prev Question
Next Question