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NCERT Class XI Mathematics - Introduction to Three Dimensional Geometry - Solutions

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Question : 19 of 20
Marks: +1, -0
A point R with x-coordinate 4 lies on the line segment joining the points P(2, –3, 4) and Q(8, 0, 10). Find the coordinates of the point R.
[Hint: Suppose R divides PQ in the ratio k : 1. The coordinates of the point R are given by (8k+2k+1,3k+1,10k+4k+1)\left(\frac{8k+2}{k+1},\frac{-3}{k+1},\frac{10k+4}{k+1}\right)]
Solution:  
Let R(4, y, z) be any point which divides the join of P(2, –3, 4) and Q(8, 0, 10) in the ratio k : 1 internally.
∴ Coordinates of R are (8k+2k+1,3k+1,10k+4k+1)\left(\frac{8k+2}{k+1},\frac{-3}{k+1},\frac{10k+4}{k+1}\right)
But x- coordinate of R is 4
8k+2k+1\frac{8k+2}{k+1} = 4
⇒ 8k + 2 = 4k + 4 ⇒ k = 12\frac{1}{2}
∴ y = 312+1\frac{-3}{\frac{1}{2}+1} = 332\frac{-3}{\frac{3}{2}} = - 2
z = 10×12+412+1\frac{\frac{10\times1}{2}+4}{\frac{1}{2}+1} = 932\frac{9}{\frac{3}{2}} = 6
Thus coordinates of R are (4, – 2, 6).
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