NCERT Class XI Mathematics - Conic Sections - Solutions

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Question : 67
Total: 71
A rod of length 12 cm moves with its ends always touching the coordinate axes. Determine the equation of the locus of a point P on the rod, which is 3 cm from the end in contact with the x-axis.
Solution:  
Let AB be a rod of length 12 cm and P(x, y) be any point on the rod such that PA = 3 cm and PB = 9 cm.
Let AR = a and BQ = b

Then ΔARP ~ ΔPQB
∴
AR
PQ
=
AP
PB

∴
a
x
=
3
9
⇒ 9a = 3x ⇒ a =
x
3

and
BQ
BP
=
PR
PA

∴
b
9
=
y
3
⇒ 3b = 9y ⇒ b = 3y
Now, OA = OR + AR = x + a = x +
x
3
=
4x
3

OB = OQ + BQ = y + b = y + 3y = 4y
In right angled ΔAOB,
AB2 = OA2 + OB2
∴ (120)2 = (
4x
3
)
2
+(4y)2
⇒ 144 =
16x2
9
+16y2

⇒
16x2
9×144
+
16y2
144
= 1 ⇒
x2
81
+
y2
9
= 1,
which is the required locus of point P and which represents an ellipse.
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