Here vertices are (±7, 0) which lie on x-axis. So, the equation of hyperbola in standard form is $\frac{x^2}{a^2} - \frac{y^2}{b^2}$ = 1. ∴ Vertices are (±7, 0) ⇒ a = 7 Now, e = $\frac{4}{3}$ ⇒ $\frac{c}{a}$ = $\frac{4}{3}$ ⇒ $\frac{c}{7}$ = $\frac{4}{3}$ ⇒ c = $\frac{28}{3}$ We know that $c^2$ = $a^2 + b^2$ ∴ $\left(\frac{28}{3}\right)^2$ = $7^2 + b^2$ ⇒ $b^2$ = $\frac{784}{9} - 49$ = $\frac{343}{9}$. Thus required equation of hyperbola is $\frac{x^2}{7^2} - \frac{y^2}{\frac{343}{9}}$ = 1 ⇒ $\frac{x^2}{49} - \frac{9y^2}{343}$ = 1.