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NCERT Class XI Mathematics - Conic Sections - Solutions

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Question : 5 of 71
Marks: +1, -0
centre (–a, –b) and radius a2−b2\sqrt{a^2-b^2}
Solution:  
Here h = –a, k = –b and r = a2−b2\sqrt{a^2-b^2}
The equation of circle is, (x−h)2+(y−k)2(x-h)^2+(y-k)^2 = r2r^2
∴ (x+a)2+(y+b)2(x+a)^2+(y+b)^2 = (a2−b2)2\left(\sqrt{a^2-b^2}\right)^2
⇒ x2+a2x^2+a^2 + 2ax + y2+b2y^2+b^2 + 2by = a2−b2a^2-b^2 ⇒ x2+y2x^2+y^2 + 2ax + 2by + 2b22b^2 = 0
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