Given equation of hyperbola is $\frac{y^2}{9} - \frac{x^2}{27}$ = 1 which is of the form $\frac{y^2}{a^2} - \frac{x^2}{b^2}$ = 1. The foci and vertices of the hyperbola lie on y-axis. Now, $a^2$ = 9 ⇒ a = 3 and $b^2$ = 27 ⇒ b = 3 $\sqrt{3}$ Also, $c^2$ = $a^2 + b^2$ = 9 + 27 = 36 ⇒ c = 6 So, coordinates of foci are (0, ±c) i.e. (0, ±6) Coordinates of vertices are (0, ±a) i.e. (0, ±3) Eccentricity (e) = $\frac{c}{a}$ = $\frac{6}{3}$ = 2 Length of latus rectum = $\frac{2b^2}{a}$ = $\frac{2 \times 27}{3}$ = 18.