Since the foci (0, ±6) lie on y-axis. ∴ The equation of ellipse in standard form is $\frac{x^2}{a^2}+\frac{y^2}{b^2}$ = 1 Now, length of minor axis 2b = 16 ⇒ b = 8, Foci are (0, ±6) ⇒ c = 6 we know that $c^2$ = $a^2 - b^2$ ∴ $(6)^2$ = $a^2 - (8)^2$ ⇒ $a^2$ = 36 + 64 = 100. Hence the required equation of ellipse is $\frac{x^2}{64}+\frac{y^2}{100}$ = 1.