Given equation of ellipse is $\frac{x^2}{100} + \frac{y^2}{400}$ = 1 Clearly, 400 > 100 The equation of ellipse in standard form is $\frac{y^2}{a^2} + \frac{x^2}{b^2}$ = 1 ∴ $a^2$ = 400 ⇒ a = 20 and $b^2$ = 100 ⇒ b = 10 We know that c = $\sqrt{a^2 - b^2}$ ⇒ c = $\sqrt{400-100}$ = $\sqrt{300}$ = $10\sqrt{3}$ ∴ Coordinates of foci are (0, ± c) i.e. (0, ± 10 $\sqrt{3}$) Coordinates of vertices are (0, ± a) i.e. (0, ± 20). Length of major axis = 2a = 2 × 20 = 40 Length of minor axis = 2b = 2 × 10 = 20 Eccentricity (e) = $\frac{c}{a}$ = $\frac{10\sqrt{3}}{20}$ = $\frac{\sqrt{3}}{2}$ Length of latus rectum = $\frac{2b^2}{a}$ = $\frac{2 \times 100}{20}$ = 10.