Given equation of ellipse is $\frac{x^2}{25}+\frac{y^2}{100}$ = 1 Clearly, 100 > 25 The equation of ellipse in standard form is $\frac{y^2}{a^2}+\frac{x^2}{b^2}$ = 1 ∴ $a^2$ = 100 ⇒ a = 10 and $b^2$ = 25 ⇒ b = 5 We know that c = $\sqrt{a^2-b^2}$ ⇒ c = $\sqrt{100-25}$ = $\sqrt{75}$ = $5\sqrt{3}$ ∴ Coordinates of foci are (0, ±c) i.e. (0, ± 5 $\sqrt{3}$) Coordinates of vertices are (0, ±a) i.e. (0, ±10). Length of major axis = 2a = 2 × 10 = 20 Length of minor axis = 2b = 2 × 5 = 10 Eccentricity (e) = $\frac{c}{a}$ = $\frac{5\sqrt{3}}{10}$ = $\frac{\sqrt{3}}{2}$ Length of latus rectum = $\frac{2b^2}{a}$ = $\frac{2\times 25}{10}$ = 5.