Given equation of ellipse is $\frac{x^2}{4} + \frac{y^2}{25}$ = 1 . Clearly, 25 > 4 The equation of ellipse in standard form is $\frac{y^2}{a^2} + \frac{x^2}{b^2}$ = 1 ∴ $a^2$ = 25 ⇒ a = 5 and $b^2$ = 4 ⇒ b = 2 We know that c = $\sqrt{a^2 - b^2}$ ⇒ c = $\sqrt{25 - 4}$ = $\sqrt{21}$ ∴ Coordinates of foci are (0, ± c) i.e. (0, ± $\sqrt{21}$) Coordinates of vertices are (0, ± a) i.e. (0, ± 5). Length of major axis = 2a = 2 × 5 = 10 Length of minor axis = 2b = 2 × 2 = 4 Eccentricity (e) = $\frac{c}{a}$ = $\frac{\sqrt{21}}{5}$ Length of latus rectum = $\frac{2b^2}{a}$ = $\frac{2 \times 4}{5}$ = $\frac{8}{5}$