Since the vertex of the parabola is at (0, 0) and the axis is along x-axis. ∴ The equation of the parabola is of the form $y^2$ = 4ax Since the parabola passes through point (2, 3) ∴ $(3)^2$ = 4a × 2 = 9 = 8a ⇒ a = $\frac{9}{8}$ The required equation of parabola is $y^2$ = $\frac{4 \times 9}{8} x$ ⇒ $y^2$ = $\frac{9}{2}$ x ⇒ $2y^2$ = 9x.