The given equation of parabola is $x^2$ = 6y, which is of the form $x^2$ = 4ay. ∴ 4a = 6 ⇒ a = $\frac{3}{2}$ ∴ Coordinates of focus are $\left(0,\frac{3}{2}\right)$ Axis of parabola is x = 0 Equation of the directrix is y = $-\frac{3}{2}$ ⇒ 2y + 3 = 0 Length of latus rectum = $\frac{4 \times 3}{2}$ = 6