We have , 27x2−10x+1 = 0
Comparing the given equation with the general form ax2 + bx + c = 0,
we get a = 27, b = – 10, c = 1
∴ x =

−b±√b2−4ac

2a

=

10±√(−10)2−4×27×1

2×27

=

10±√100−108

54

=

10±√−8

54

=

10±i√8

54

=

5±i√2

27