We have, x2 + 3x + 5 = 0
Comparing the given equation with the general form ax2 + bx + c = 0,
we get a = 1, b = 3, c = 5.
∴ x =

−b±√b2−4ac

2a

=

−3±√(3)2−4×1×5

2

=

−3±√9−20

2

=

−3±√−11

2

=

−3±√11

2

∴ The roots of the given equation are

−3+√−11

2

and

−3−√−11

2