We have, x2 + 3x + 9 = 0
Comparing the given equation with the general form ax2 + bx + c = 0,
we get a = 1, b = 3, c = 9
∴ x =

−b±√b2−4ac

2a

=

−3±√(3)2−4×1×9

2.1

=

−3±√9−36

2

=

−3±√−27

2

=

−3±3√−3

2

=

−3±i(3√3)

2

∴ The roots of the given equation are

−3+i(3√3)

2

and

−3−i(3√3)

2