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NCERT Class XI Mathematics - Complex Numbers and Quadratic Equations - Solutions

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Question : 6 of 52
Marks: +1, -0
(15+i25)−(4+i52)\left(\frac{1}{5}+i\frac{2}{5}\right)-\left(4+i\frac{5}{2}\right)
Solution:  
(15+i25)−(4+i52)\left(\frac{1}{5}+i\frac{2}{5}\right)-\left(4+i\frac{5}{2}\right) = 15+i25\frac{1}{5} + i\frac{2}{5} - 4 - i52i\frac{5}{2} = (15−4)\left(\frac{1}{5}-4\right) + i (25−52)\left(\frac{2}{5}-\frac{5}{2}\right)
= (1−205)+i(4−2510)\left(\frac{1-20}{5}\right)+i\left(\frac{4-25}{10}\right) = −195−2110\frac{-19}{5} - \frac{21}{10} i = (−195)+(−2110)i\left(\frac{-19}{5}\right)+\left(\frac{-21}{10}\right)i
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