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NCERT Class XI Mathematics - Complex Numbers and Quadratic Equations - Solutions

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Question : 38 of 52
Marks: +1, -0
3x2−4x+203=03x^2 - 4x + \frac{20}{3} = 0
Solution:  
We have, 3x2−4x+203=03x^2 - 4x + \frac{20}{3} = 0 Comparing the given equation with the general form ax2ax^2 + bx + c = 0,
we get
a = 3 , b = - 4 , c = 203\frac{20}{3}
∴ x = −b±b2−4ac2a\frac{-b \pm \sqrt{b^2 - 4ac}}{2a} = −(−4)±(−4)2−4×3×2032×3\frac{-(-4) \pm \sqrt{(-4)^2 - 4 \times 3 \times \frac{20}{3}}}{2 \times 3}
= 4±16−806\frac{4 \pm \sqrt{16 - 80}}{6} = 4±−616\frac{4 \pm \sqrt{-61}}{6} = 4±8i6\frac{4 \pm 8i}{6} = 2±4i3\frac{2 \pm 4i}{3} = 23±43i\frac{2}{3} \pm \frac{4}{3} i
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