We have , $-x^2$ + x - 2 = 0 Comparing the given equation with the general form $ax^2$ + bx + c = 0, we get a = –1, b = 1, c = –2. ∴ x = $\frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$ = $\frac{-1 \pm \sqrt{(1)^2 - 4 \times (-1) \times (-2)}}{2(-1)}$ = $\frac{-1 \pm \sqrt{1-8}}{-2}$ = $\frac{-1 \pm \sqrt{-7}}{-2}$ = $\frac{-1 \pm i\sqrt{7}}{-2}$ ∴ The roots of the given equation are $\frac{-1 + i\sqrt{7}}{-2}$ and $\frac{-1 - i\sqrt{7}}{-2}$