NCERT Class XI Mathematics - Binomial Theorem - Solutions

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Question : 23
Total: 36
In the expansion of (1+a)m+n, prove that coefficients of am and an are equal.
Solution:  
Suppose am occurs in the (r + 1)th term in the expansion of (1+a)m+n.
Now Tr+1 =
m+n
‌
Cr(1)m+n−r(a)r
=
m+n
‌
Crar

On comparing power of a in am and Tr+1, we get r = m.
Thus the coefficient of am is
m+n
‌
Cm
=
(m+n)!
m!(m+n−m)!
=
(m+n)!
m!n!
... (i)
Suppose an occurs in the (r + 1)th term in the expansion of (1+a)m+n.
On comparing power of a in an and Tr+1, we get, r = n
Thus the coefficient of an is
m+n
‌
Cn
=
(m+n)!
n!(m+n−n)!
=
(m+n)!
n!m!
... (ii)
From (i) & (ii) we proved that coefficient of am & an in expansion (1+a)m+n are equal.
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