Test Index

NCERT Class XI Mathematics - Binomial Theorem - Solutions

© examsnet.com
Question : 8 of 36
Marks: +1, -0
(101)4(101)^4
Solution:  
We have, 101 = 100 + 1
∴ (101)4(101)^4 = (100+1)4(100+1)^4
= 4C0(100)4+4C1(100)3{}^{4}C_0(100)^4+{}^{4}C_1(100)^3 + 4C2(100)2+4C3(100)+4C4(100)0{}^{4}C_2(100)^2+{}^{4}C_3(100)+{}^{4}C_4(100)^0
= 100000000 + 4(1000000) + 6 (10000) + 400 + 1
= 100000000 + 4000000 + 60000 + 400 + 1= 104060401
© examsnet.com
Go to Question:
Prev Question
Next Question