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NCERT Class XI Mathematics - Binomial Theorem - Solutions

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Question : 6 of 36
Marks: +1, -0
(96)3(96)^3
Solution:  
We have, 96 = 100 - 4
∴ (96)3(96)^3 = (100−4)3(100-4)^3
= (30)(100)3+(31)(100)2(−4)\binom{3}{0}(100)^3+\binom{3}{1}(100)^2(-4) + (32)(100)(−4)2+(33)(−4)3\binom{3}{2}(100)(-4)^2+\binom{3}{3}(-4)^3
= (100)3+3(100)2(−4)(100)^3+3(100)^2(-4) + 3 (100) (16) + (- 64)
= 1000000 - 120000 + 4800 - 64 = 884736
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