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NCERT Class XI Mathematics - Binomial Theorem - Solutions

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Question : 1 of 36
Marks: +1, -0
(1−2x)5(1-2x)^5
Solution:  
We have , (1−2x)5(1-2x)^5 = [1+(−2x)]5[1+(-2x)]^5
=
5C0+5C1(−2x)+5C2(−2x)2+5C3(2x)3+5C4(−2x)4+5C5(−2x)5{}^5C_0 + {}^5C_1 (-2x) + {}^5C_2 (-2x)^2 + {}^5C_3 (2x)^3 + {}^5C_4 (-2x)^4 + {}^5C_5 (-2x)^5
= 1 + 5 (- 2x) + 10 (4x2)(4x^2) + 10 (−8x3)+5(16x4)+(−32x5)(-8x^3) + 5(16x^4) + (-32x^5)
= 1 - 10x + 40x2−80x3+80x4−32x540x^2-80x^3+80x^4-32x^5
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