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NCERT Class XI Chemistry Thermodynamics Solutions

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Question : 20 of 22
Marks: +1, -0
The equilibrium constant for a reaction is 10. What will be the value of ΔG° ?
R = 8.314 JK–1mol–1J K^{–1} mol^{–1}, T = 300 K.
Solution:  
We know that ΔG° = –2.303RT logK = –2.303 × 8.314 × 300 × log10
= –5744.14 J/mol
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