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NCERT Class XI Chemistry The s-Block Elements Solutions
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Question : 16 of 32
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Starting with sodium chloride how would you proceed to prepare (i) sodium metal (ii) sodium hydroxide (iii) sodium peroxide (iv) sodium carbonate ?
Solution:
(i) Sodium metal is prepared by electrolysis of fused NaCl at 873 K using iron cathode and graphite anode (Down’s cell). NaCl ⇌ At anode : → → At cathode : → Na (ii) Sodium hydroxide is prepared by electrolysis of aqueous solution of NaCl using Hg cathode and carbon anode. (Castner-Kellner cell) : NaCl ⇌ At cathode : Na-amalgam At anode : → Na - amalgam is treated with water to give NaOH and : 2Na-amalgam + → (iii) Sodium chloride to sodium peroxide : NaCl ⇌ At anode : → → At cathode : → Na Sodium is heated in excess of air. 2Na + . (iv) Sodium hydrogen carbonate is prepared by passing through NaCl solution saturated with formed is heated to give . (Solvay process) : + NaCl → 2NaHCO3 Na2CO3 + H2O + CO2
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