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NCERT Class XI Chemistry The p-Block Elements Solutions

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Question : 20 of 38
Marks: +1, -0
What happens when :
(a) Borax is heated strongly.
(b) Boric acid is added to water.
(c) Aluminium is treated with dilute NaOH.
(d) BF3\mathrm{BF}_3 is reacted with ammonia.
Solution:  
(a) When powdered borax is heated strongly on the bunsen burner, it forms colourless transparent glassy (glass like) bead made of sodium metaborate and boric anhydride.
Na2B4O710H2O\mathrm{Na}_2\mathrm{B}_4\mathrm{O}_7 \cdot 10\mathrm{H}_2\mathrm{O} Heat\xrightarrow{Heat} Na2B4O7\mathrm{Na}_2\mathrm{B}_4\mathrm{O}_7 Heat\xrightarrow{Heat} 2NaBO2+B2O3Transparent glassy bead\underset{\text{Transparent glassy bead}}{2\mathrm{NaBO}_2+\mathrm{B}_2\mathrm{O}_3}
(b) It dissolves in water behaving as Lewis acid. It forms [B(OH)4][\mathrm{B}(\mathrm{OH})_4]^{-} by accepting a pair of electrons from OH–.
B(OH)3+HOH\mathrm{B}(\mathrm{OH})_3 + \mathrm{H}-\mathrm{OH}[B(OH)4]+H+[\mathrm{B}(\mathrm{OH})_4]^{-} + \mathrm{H}^{+}.
(c) Aluminium dissolves in NaOH solution to form a soluble complex and liberates hydrogen gas.
2Al(s)+2NaOH(aq)+6H2O(l)2\mathrm{Al}_{(s)} + 2\mathrm{NaOH}_{(aq)} + 6\mathrm{H}_2\mathrm{O}_{(l)}2Na[Al(OH)4](aq)Soluble complex+3H2(g)\underset{\text{Soluble complex}}{2\mathrm{Na}[\mathrm{Al}(\mathrm{OH})_4]_{(aq)}} + 3\mathrm{H}_{2(g)}
(d) BF3\mathrm{BF}_3 (Lewis acid in nature) forms an addition compound with NH3\mathrm{NH}_3 (Lewis base in nature).
FBFFLewis base (Acceptor)\underset{\text{Lewis base (Acceptor)}}{\mathrm{F}-\overset{\overset{\mathrm{F}}{\vert}}{\underset{\underset{\mathrm{F}}{\vert}}{\mathrm{B}}}} + :NHHHLewis base (Donor)\underset{\text{Lewis base (Donor)}}{:\overset{\overset{\mathrm{H}}{\vert}}{\underset{\underset{\mathrm{H}}{\vert}}{\mathrm{N}}}-\mathrm{H}}[FBFF:NHHH]Addition compound\underset{\text{Addition compound}}{\left[\mathrm{F}-\overset{\overset{\mathrm{F}}{\vert}}{\underset{\underset{\mathrm{F}}{\vert}}{\mathrm{B}}} \leftarrow :\overset{\overset{\mathrm{H}}{\vert}}{\underset{\underset{\mathrm{H}}{\vert}}{\mathrm{N}}}-\mathrm{H}\right]}
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