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NCERT Class XI Chemistry Structure of Atom Solutions

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Question : 17
Total: 67
Calculate the wavenumber for the longest wavelength transition in the Balmer series of atomic hydrogen.
Solution:  
According to Rydberg equation,
1
λ
 =
−
v
(cm−1) = R(
1
n12
−
1
n22
) = 109678 (
1
22
−
1
32
) = 109678 (
1
4
−
1
9
)
= 109678 ×
5
36
cm−1 = 1.5233 × 104cm−1
Wavenumber of Balmer series = 1.523 × 106m–1
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